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1.5x^2-2x-1=0
a = 1.5; b = -2; c = -1;
Δ = b2-4ac
Δ = -22-4·1.5·(-1)
Δ = 10
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-\sqrt{10}}{2*1.5}=\frac{2-\sqrt{10}}{3} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+\sqrt{10}}{2*1.5}=\frac{2+\sqrt{10}}{3} $
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